50x^2-5x-105=0

Solution for 50x^2-5x-105=0 equation:

50x^2-5x-105=0

a = 50; b = -5; c = -105;
Δ = b2-4ac
Δ = -52-4·50·(-105)
Δ = 21025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{21025}=145$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-145}{2*50}=\frac{-140}{100}
=-1+2/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+145}{2*50}=\frac{150}{100}
=1+1/2
$